20x^2-33x+10=0

Solution for 20x^2-33x+10=0 equation:

20x^2-33x+10=0

a = 20; b = -33; c = +10;
Δ = b2-4ac
Δ = -332-4·20·10
Δ = 289
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{289}=17$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-33)-17}{2*20}=\frac{16}{40}
=2/5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-33)+17}{2*20}=\frac{50}{40}
=1+1/4
$